Discussion :: Transformers  General Questions (Q.No.8)
8.  The mutual inductance when k = 0.65, L_{1} = 2 H, and L_{2} = 5 H is 

Answer: Option B Explanation: No answer description available for this question.

Waseem Guru said: (Dec 13, 2010)  
M = Mutual Inductance M = k*(L1*L2)^1/2 M = 0.65(10)^1/2 M = 2uH 
Naresh said: (Aug 11, 2011)  
I did not understand the formula clearly. 
Archu said: (Aug 14, 2011)  
k=M/(L1*L2)^1/2 
Yousuf said: (Sep 29, 2011)  
This formula is correct. It is related to coupling coefficient. 
Kondalu said: (Nov 5, 2011)  
It is correct. 
Ankit said: (Mar 20, 2012)  
k=M/(L1*L2)^1/2 
Vijay Balu Raskar said: (Mar 25, 2012)  
Formula is correct. 
Ganesh said: (Apr 13, 2012)  
M=MUTUAL Inductance M=K(L1*L2)^1/2 
Balagangadhara said: (Apr 16, 2012)  
I did not understand the formula used to data clearly. 
Siri said: (May 24, 2012)  
K=M/sqrt(L1*L2)...............(According to coefficient of coupling) i.e M=K*sqrt(L1*L2) =.65*sqrt(5*10) =.65*3.15 =2.055 Appox=2 
Santosh said: (Jun 8, 2012)  
M=k*sqrt(L1*L2) this is according to the coupling coefficent 
Nidhi said: (Jun 10, 2012)  
Coefficient of coupling k=M/(sqrt(L1*L2)) Therefore M=K*[sqrt(L1*L2)] 
S.Anjineyulu Naik said: (Oct 1, 2012)  
Mutual inductance, M=k*sqrt(L1*L2) =0.65*3.162 =2 
Lakshmi Nagesh said: (Nov 14, 2012)  
formula is perfect M = K(sqrt(L1*L2)) M= 0.65(sqrt(2*10^6 * 5* 10^6)) = 0.65(sqrt(2*5))(sqrt(10^12)) = 0.65(3.162)(10^6) = 2micro Henry. 
Harika Gadde said: (Dec 21, 2012)  
Formula is Coupling Coefficient K=M/(sqrt(L1*L2)) 
Panduu said: (Feb 10, 2013)  
k=coupling coefficient. m=mutual inductance. L1=inductance1. L2=inductance2. k=m/SQUARE ROOT OF(L1*L2). 
Suyog Shrivastava said: (Jun 11, 2013)  
According to coefficient of coupling, K = M/sqrt(L1*L2). where , M = K*sqrt(L1*L2). M = 0.65*sqrt(5*10). M = 0.65*3.15. M = 2. 
Shyama Sundar Jena said: (Aug 29, 2013)  
M = K*^1/2(L1*L2). So M = 0.65*3.15. = approx 2micro H 
V N Bhoyar said: (Jul 20, 2014)  
M = k sq. root of L1*L2. 
Rajiv Nautiyal said: (Dec 18, 2014)  
Is it 2 micro H or 2 milli H? 
Pramod Rps said: (Feb 6, 2015)  
Its micro obviously. 
Priyanka said: (Jun 18, 2015)  
L2=5, not 10 hows write 10. 
P Venkateswara Reddy said: (Aug 25, 2015)  
As we know that M = K (L1*L2)^(1/2). M = 0.65*(2*5*10^6*10^6)^(1/2) = 2 uH. 
Nakul said: (Dec 11, 2015)  
I can't understand this example, please explain. 
Sravanthi said: (Apr 20, 2016)  
The correct formulae are k=M/(L1*L2)^1/2. 
Shekar said: (Aug 30, 2016)  
M = k * (L1 L2)^1/2 . 
Jittu said: (Dec 25, 2016)  
Good answer. Thanks you all. 
Manjunath Ukkali said: (Dec 29, 2016)  
Not getting it. Please help me. 
P. Rajesh said: (Mar 11, 2017)  
How to apply 5*10 in sum? 
Shenbalaxmi said: (Apr 11, 2017)  
KCoupling factor L1,L2Self inductance MMutual inductance M = K * sqrt(L1 * L2), M = 0.65 * (2x10^6x5x10^6). M = 2microHenry. 
Juber Alam said: (Apr 17, 2017)  
The coefficient of coupling K=M/(SqrtL1*L2). 
Anil said: (Apr 29, 2017)  
Mutual inductance: coefficient of coupling * √ inductance. 
Kanyasri said: (Jun 7, 2017)  
M = K(L1 * L2)^1/2, M = 0.65(10)^1/2, M = 2UH. 
Kanyasri said: (Jun 7, 2017)  
Formula M^2 = (L1 * L2). 
Abhishek said: (Aug 29, 2017)  
It is 2M/L1*L2. 
Muhammed said: (Aug 8, 2018)  
Thank you for the explanation. 
Avnish Kumar said: (Oct 3, 2018)  
Nice, Thanks for giving this section. 
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